Respuesta :

Answer:

Graph the two points (0,1) and (2,-1) then connect them with a straight edge.

Step-by-step explanation:

The transformed graph is still a line since the parent is a line.

[tex]g(x)=\frac{-1}{2}f(x+2)[/tex]

Identify two points that cross nicely on your curve for f:

(2,-2) and (4,2)

So I'm going to replace x in x+2 so that x+2 is 2 and then do it also for when x+2 is 4.

x+2=2 when x=0 since 0+2=2.

x+2=4 when x=2 since 2+2=4.

So plugging in x=0:

[tex]g(x)=\frac{-1}{2}f(x+2)[/tex]

[tex]g(0)=\frac{-1}{2}f(0+2)[/tex]

[tex]g(0)=\frac{-1}{2}f(2)[/tex]

[tex]g(0)=\frac{-1}{2}(-2)[/tex] since we had the point (2,-2) on line f.

[tex]g(0)=1[/tex] so g contains the point (0,1).

So plugging in the other value we had for x, x=2:

[tex]g(x)=\frac{-1}{2}f(x+2)[/tex]

[tex]g(2)=\frac{-1}{2}f(2+2)[/tex]

[tex]g(2)=\frac{-1}{2}f(4)[/tex]

[tex]g(2)=\frac{-1}{2}(2)[/tex] since we had the point (4,2) on the line f.

[tex]g(2)=-1[/tex] so g contains the point (2,-1).

Graph the two points (0,1) and (2,-1) then connect them with a straight edge.