Answer:
[tex]96x^4y+104x^2y^2[/tex]
is the simplified form of
your given problem:
[tex](12x^2+13y)(4x \times 2xy)[/tex].
Step-by-step explanation:
So the given problem is this:
[tex](12x^2+13y)(4x \times 2xy)[/tex]
I'm going to do the multiplication in the second ( ).
Nothing can be done in the first ( ) because the operation is addition and those two terms aren't like terms.
[tex](12x^2+13y)(8x^2y)[/tex]
I got x^2 because of x(x) part.
Now we get to distribute 8x^2y to both terms in the ( ).
[tex]12x^2 \cdot 8x^2y+13y \cdot 8x^2y[/tex]
Adding exponents on bases that have the same variable:
[tex]96x^4y+104x^2y^2[/tex]
