Answer:
-3c
Step-by-step explanation:
We are given that an expression
[tex]\frac{\frac{6c^2+3c}{-4c+2}}{\frac{2c+1}{4c-2}}[/tex]
We have to find an expression which is equal to given expression
Taking common 3c from nominator and -2 from denominator in dividened and 2 common in divisor then we get
[tex]\frac{\frac{3c(2c+1)}{-2(c-2)}}{\frac{2c+1}{2(2c-1)}}[/tex]
[tex]\frac{3c(2c+1)}{-2(2c-1)}\times \frac{2(2c-1)}{(2c+1)}[/tex]
By reciprocal divisor
By canceling same factor
Then ,we get
[tex]\frac{\frac{6c^2+3c}{-4c+2}}{\frac{2c+1}{4c-2}}[/tex]
=-3c
