Answer:
Option C (2556.1 meters).
Step-by-step explanation:
This question can be solved using one of the three trigonometric ratios. The height of the airplane from the ground is 1200 meters and the angle of depression is 28°. It can be seen that the required distance is given by x meters. This forms a right angled triangle, as it can be seen in the diagram. The perpendicular is given by 1200 meters, the hypotenuse is unknown, and the angle of 28° is given, as shown in the attached diagram. Therefore, the formula to be used is:
sin θ = Perpendicular/Hypotenuse.
Plugging in the values give:
sin 28 = 1200/x.
x = 1200/sin 28.
x = 2556.06536183 meters.
Therefore, the airplane is 2556.1 meters (to the nearest tenths) far away from the building!!!
