Which of the following are solutions to the equation below?
Check all that apply.
(3x + 4)2 = 14

Answer:
F and E
Step-by-step explanation:
[tex](3x+4)^2=14[/tex]
We could get rid of the square on the (3x+4) by square rooting both sides:
[tex]3x+4=\pm \sqrt{14}[/tex]
Now you are left with a linear equation to solve.
Subtract 4 on both sides:
[tex]3x=-4 \pm \sqrt{14}[/tex]
Divide both sides by 3:
[tex]x=\frac{-4 \pm \sqrt{14}}{3}[/tex]
You could rearrange the numerator using commutative property:
[tex]x=\frac{\pm \sqrt{14}-4}{3}[/tex]
If you wanted two write the two answers out, you would write:
[tex]x=\frac{\sqrt{14}-4}{3} \text{ or } \frac{-\sqrt{14}-4}{3}[/tex].
So I see this in F and E.
You could separate the fraction:
[tex]x=\frac{\sqrt{14}}{3}-\frac{4}{3} \text{ or } -\frac{\sqrt{14}}{3}-\frac{4}{3}[/tex].