Answer:
[tex]P=\dfrac{1}{24}[/tex]
Step-by-step explanation:
Let the names of 4 players start with letters A, B, C and D.
There is the the only chance that they shoot free throws in alphabetical order (ABCD).
Count how many different ways are to choose 4 letters from the hat. First letter can be chosen in 4 ways, the second letter can be chosen in 3 ways (only 3 letters left), the third letter can be chosen in 2 ways (only 2 letters left) and the fourth letter can be chosen in 1 way (the last letter left). So, there are
[tex]4\cdot 3\cdot 2\cdot 1=24[/tex]
different orders.
The probability is
[tex]P=\dfrac{1}{24}[/tex]