At a certain distance from a pole, the angle of elevation to the top of the pole is 28° . If the pole is 6.3 ft tall, what is the distance from the pole?

The given scenario will form a right angled triangle where the distance and the point from where the angle of elevation is measured will be the base of the triangle.

We know

Angle of elevation = x = 28 °

Height of pole = p = 6.3 feet

Distance from pole = d= ?

So,

[tex]tan\ x = \frac{p}{b}\\ tan\ 28 = \frac{6.3}{b} \\0.5317 = \frac{6.3}{b}\\b = \frac{6.3}{0.5317}\\b=11.84\ feet[/tex]

Therefore, the distance from the pole is 11.84 feet ..

At a certain distance from a pole, the angle of elevation to the top of the pole is 28° . If the pole is 6.3 ft tall, what is the distance from the pole?​

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At a certain distance from a pole, the angle of elevation to the top of the pole is 28° . If the pole is 6.3 ft tall, what is the distance from the pole?