Answer:
0.833 seconds
Explanation:
Given:
y₀ = 0 m
y = 0 m
v₀ = 4.47 sin 66° m/s
a = -9.80 m/s²
Find: t
y = y₀ + v₀ t + ½ at²
0 = 0 + (4.47 sin 66°) t + ½ (-9.80) t²
0 = 4.08 t − 4.90 t²
0 = t (4.08 − 4.90 t)
t = 0, 0.833
It takes 0.833 seconds to return to its original launching height.
