What is the value of sec
in the triangle below?
41 ft
9 ft
40 ft

Answer:
C
Step-by-step explanation:
[tex] \sec( \alpha ) = \frac{1}{ \cos( \alpha ) } \\ \\ \sec( \alpha ) = \frac{1}{ \frac{ad}{hip} } \\ \\ \sec( \alpha ) = \frac{hip}{ad} \\ \\ \sec( \alpha ) = \frac{41}{40} [/tex]
The value of the secθ is 41/40.
Trigonometry is mainly concerned with specific functions of angles and their application to calculations. Trigonometry deals with the study of the relationship between the sides of a triangle (right-angled triangle) and its angles.
For the given situation,
The diagram shows the right-angled triangle.
The sides of the right-angled triangle are
Hypotenuse side = 41 ft
Opposite side = 9 ft
Adjacent side = 40 ft
The value of secθ is
[tex]sec \theta =\frac{1}{cos \theta}[/tex]
where, [tex]cos \theta =\frac{adjacent}{hypotenuse}[/tex]
⇒ [tex]sec \theta =\frac{hypotenuse}{adjacent}[/tex]
⇒ [tex]sec \theta =\frac{41}{40}[/tex]
Hence we can conclude that the value of the secθ is 41/40.
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