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You need a 30% alcohol solution. On hand, you have a 200 mL of a 10% alcohol mixture. You also have 55% alcohol mixture. How much of the 55% mixture will you need to add to obtain the desired solution?

Respuesta :

Answer: 160 ml

Explanation:

The expression used will be :

[tex]C_1V_1+C_2V_2=C_3V_3[/tex]

where,

[tex]C_1[/tex] = concentration of Ist alcohol solution= 10%

[tex]C_2[/tex] = concentration of 2nd alcohol solution= 55%

[tex]V_1[/tex] = volume of Ist alcohol solution = 200 ml

[tex]V_2[/tex] = volume of  2nd alcohol solution= v ml

[tex]C_3[/tex] = concentration of resulting alcohol solution= 30%

[tex]V_2[/tex] = volume of resulting alcohol solution= (v+200) ml

Now put all the given values in the above law, we get the volume of added.

[tex](10\times 200)+(55\times v)=(30\times (v+200)ml)[/tex]

By solving the terms, we get :

[tex]v=160ml[/tex]

Therefore, the volume of 55% mixture  needed to be added to obtain the desired solution is 160 ml.

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