Answer:
(4273.7 [tex]\hat{j}[/tex] - 3281.6 [tex]\hat{i}[/tex])
Explanation:
[tex]\underset{v_{i}}{\rightarrow}[/tex] = initial velocity of the baseball before collision = 43 [tex]\hat{i}[/tex] m/s
[tex]\underset{v_{f}}{\rightarrow}[/tex] = final velocity of the baseball after collision = 56 [tex]\hat{j}[/tex] m/s
m = mass of the ball = 145 g = 0.145 kg
t = time of contact of the ball with the bat = 1.90 ms = 0.0019 s
[tex]\underset{F_{avg}}{\rightarrow}[/tex] = Average force vector
Using Impulse-change in momentum equation
[tex]\underset{F_{avg}}{\rightarrow}[/tex] t = m ([tex]\underset{v_{f}}{\rightarrow}[/tex] - [tex]\underset{v_{i}}{\rightarrow}[/tex] )
[tex]\underset{F_{avg}}{\rightarrow}[/tex] (0.0019) = (0.145) (56 [tex]\hat{j}[/tex] - 43 [tex]\hat{i}[/tex])
[tex]\underset{F_{avg}}{\rightarrow}[/tex] = (4273.7 [tex]\hat{j}[/tex] - 3281.6 [tex]\hat{i}[/tex])
