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Please help me!
The angle of elevation of the top of a tower to a point on the ground is 61°. At a point 600 feet farther from the base, in line with the base and the first point and in the same plane, the angle of elevation is 32°. Find the height of the tower.

Respuesta :

Answer:

  573.6 ft

Step-by-step explanation:

The mnemonic SOH CAH TOA reminds you of the relationship of right triangle sides and angles:

  Tan = Opposite/Adjacent

This tells us ...

  tan(61°) = (height)/(distance to first point)

or

  distance to first point = height/tan(61°)

Likewise, ...

  distance to second point = height/tan(32°)

Then the difference of the distances is ...

  distance to second point - distance to first point

     = height/tan(32°) -height/tan(61°)

  600 ft = height × (1/tan(32°) -1/tan(61°))

Dividing by the coefficient of height, we have ...

  height = (600 ft)/(1/tan(32°) -1/tan(61°)) ≈ (600 ft)/(1.04603) ≈ 573.6 ft

Answer:

574

Step-by-step explanation: