contestada

The reaction X 2 (g) m 2 X(g) occurs in a closed reaction vessel at constant volume and temperature. Initially, the vessel contains only X 2 at a pressure of 1.55 atm. After the reaction reaches equilibrium, the total pressure is 2.85 atm. What is the value of the equilibrium constant, Kp , for the reaction?

Respuesta :

Answer:

41.6 is the value of the equilibrium constant for the reaction.

Explanation:

           [tex]X_2\rightleftharpoons 2X[/tex]

Initially   1.55            0

At eq'm  1.55-p        2p

Total pressure at the equilibrium = P =2.85 atm

[tex]P=(1.55-p)+2 p = 2.85 atm[/tex]

p = 1.3 atm

Partial pressure of [tex]X_2[/tex] at equilibrium:

[tex][p_{X_2}^o]=2p=2\time 1.3 atm=2.6 atm[/tex]

Partial pressure of X at equilibrium;

[tex][p_{X}^{o}]=1.55 atm -1.3 atm = 0.25 atm[/tex]

The value of equilibrium constant will be given as:

[tex]K_p=\frac{[p_{X_2}^o]}{[p_{X}^{o}]^2}[/tex]

[tex]K_p=\frac{2.6 atm}{(0.25 atm)^2}=41.6[/tex]

Otras preguntas