Respuesta :
Answer:
acceleration in the new orbit is 8 time of acceleration of planet in old orbit
[tex]a_{new} = 8a.[/tex]
Explanation:
given data:
radius of orbit = R
Speed pf planet = v
new radius = 0.5R
new speed = 2v
we know that acce;ration is given as
[tex]a = \frac{v^{2}}{R},[/tex]
[tex]a_{new} =\frac{(2v)^{2}}{0.5R},[/tex]
[tex]= \frac{4v^{2}}{0.5R}[/tex]
[tex]= \frac{8 v^{2}}{R}[/tex]
[tex]a_{new} = 8a.[/tex]
acceleration in the new orbit is 8 time of acceleration of planet in old orbit
The magnitude of the probe’s acceleration in the new orbit is 8 times the magnitude of the probe’s acceleration in the old orbit.
What is centripetal acceleration?
The acceleration acted on the body moving in a closed circular path towards the center of the curve is known as centripetal acceleration. Due to centripetal acceleration, the body is able to move in a closed circular path.
[tex]a_C=\frac{V^{2} }{R}[/tex]
For old orbit
the radius of orbit = R
Speed pf planet = v
[tex]a_C=\frac{V^{2} }{R}[/tex]
For new orbits
new radius = 0.5R
new speed = 2v
[tex]a_C=\frac{(2V)^{2} }{0.5R}[/tex]³
[tex]a_C=\frac{8V^{2} }{R}[/tex]
Hence,
[tex]a_C_{new}=8a_C__{old}[/tex]
The magnitude of the probe’s acceleration in the new orbit is 8 times the magnitude of the probe’s acceleration in the old orbit.
To learn more about centripetal acceleration refers to the link
https://brainly.com/question/17689540
