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In reverse osmosis, water flows out of a salt solution until the osmotic pressure of the solution equals the applied pressure. If a pressure of 70.0 bar is applied to seawater, what will be the final concentration of the seawater at 20 ∘C when reverse osmosis stops?

Respuesta :

Answer : The final concentration of the seawater is, 2.909 mole/L

Explanation :

Formula used for osmotic pressure :

[tex]\pi=CRT[/tex]

where,

[tex]\pi[/tex] = osmotic pressure  = 70.0 bar = 70 atm

R = solution constant  = 0.0821 Latm/moleK

T= temperature of solution = [tex]20^oC=273+20=293K[/tex]

C = final concentration of seawater = ?

Now put all the given values in the above formula, we get the concentration of seawater.

[tex]70atm=C\times 0.0821Latm/moleK\times 293K[/tex]

[tex]C=2.909mole/L[/tex]

Therefore, the final concentration of the seawater is, 2.909 mole/L

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