Answer:
[tex]\beta = 41.68°[/tex]
Explanation:
according to snell's law
[tex]\frac{n_w}{n_g} = \frac{sin\alpha}{sin30 }[/tex]
refractive index of water n_w is 1.33
refractive index of glass n_g is 1.5
[tex]sin\alpha = \frac{n_w}{n_g}* sin30[/tex]
[tex]sin\alpha = 0.443[/tex]
now applying snell's law between air and glass, so we have
[tex]\frac{n_g}{n_a} = \frac{sin\alpha}{sin\beta}[/tex]
[tex]sin\beta = \frac{n_g}{n_a} sin\alpha[/tex]
[tex]\beta = sin^{-1} [\frac{n_g}{n_a}*sin\alpha][/tex]
we know that [tex]sin\alpha = 0.443[/tex]
[tex]\beta = 41.68°[/tex]
