Respuesta :

gmany

Answer:

[tex]\large\boxed{y=4x+3}[/tex]

Step-by-step explanation:

The slope-intercept form of an equation of aline:

[tex]y=mx+b[/tex]

m - slope

b - y-intercept

The formula of a slope:

[tex]m=\dfraxc{y_2-y_1}{x_2-x_1}[/tex]

From the graph we have the points:

(-2, -5)

y-intercept (0, 3) → b = 3

Calculate the slope:

[tex]m=\dfrac{3-(-5)}{0-(-2)}=\dfrac{8}{2}=4[/tex]

Put the value of the slope and the y-intercept to the equation of a line:

[tex]y=4x+3[/tex]

The required equation of the line is y = 4x - 3

The standard formula for calculating the equation of a line is expressed as;

[tex]y=mx+b[/tex]

m is the slope

b is the y-intercept

From the graph, we can use the coordinate (0, 3) and (-2, -5)

Get the slope:

[tex]m=\frac{y_2-y_1}{x_2-x_1} \\m=\frac{-5-3}{-2-0}\\m=\frac{-8}{-2}\\m=4\\[/tex]

From the given diagram, the y-intercept is of the line is at b = 3

Get the required equation:

[tex]y=mx+b\\y=4x+(-3)\\y=4x-3\\\\[/tex]

Hence the required equation is y = 4x - 3

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