Write an equation of the line below.

Answer:
[tex]\large\boxed{y=4x+3}[/tex]
Step-by-step explanation:
The slope-intercept form of an equation of aline:
[tex]y=mx+b[/tex]
m - slope
b - y-intercept
The formula of a slope:
[tex]m=\dfraxc{y_2-y_1}{x_2-x_1}[/tex]
From the graph we have the points:
(-2, -5)
y-intercept (0, 3) → b = 3
Calculate the slope:
[tex]m=\dfrac{3-(-5)}{0-(-2)}=\dfrac{8}{2}=4[/tex]
Put the value of the slope and the y-intercept to the equation of a line:
[tex]y=4x+3[/tex]
The required equation of the line is y = 4x - 3
The standard formula for calculating the equation of a line is expressed as;
[tex]y=mx+b[/tex]
m is the slope
b is the y-intercept
From the graph, we can use the coordinate (0, 3) and (-2, -5)
Get the slope:
[tex]m=\frac{y_2-y_1}{x_2-x_1} \\m=\frac{-5-3}{-2-0}\\m=\frac{-8}{-2}\\m=4\\[/tex]
From the given diagram, the y-intercept is of the line is at b = 3
Get the required equation:
[tex]y=mx+b\\y=4x+(-3)\\y=4x-3\\\\[/tex]
Hence the required equation is y = 4x - 3
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