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A 1 kg ball is loaded into a spring gun with a spring constant of 105 N/m. If the spring iscompressed by 0.1 m and the ball is shot up vertically, how high does it rise into the air from thepoint where it leaves the spring?

Respuesta :

Answer:

H = 5.35 cm

Explanation:

As per energy conservation we know that energy stored in the spring is converted into gravitational potential energy when it is reached at the top

now we have

[tex]\frac{1}{2}kx^2 = mgh[/tex]

here we know that

m = 1 kg

k = 105 N/m

x = 0.1 m

now plug in all data in it

[tex]\frac{1}{2}(105)(0.1^2) = 1(9.81)(H)[/tex]

now solving for height H we have

[tex]H = 0.0535 m[/tex]

[tex]H = 5.35 cm[/tex]

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