Write a mathematical expression for the area of the triangle as a function of the length of the base. Use the letter s to represent the length of the base of the triangle described below. The base of an isosceles triangle is one eighth as long as the two equal sides.

Respuesta :

Answer:

  A = s²√15.9375

Step-by-step explanation:

An altitude of the triangle divides it into two right triangles, each with a leg of s/2 and a hypotenuse of 8s. Then the length of the altitude (h) is given by the Pythagorean theorem as ...

  h² + (s/2)² = (8s)²

  h = s√(64 -1/4) . . . . . . . subtract s²/4 and take the square root

Then the area is ...

  A = (1/2)sh = (s/2)(s√63.75)

We can put all the constants in one place to get ...

  A = s²√15.9375

The area of a triangle is the product of its base and height, divided by 2. The mathematical expression for the area of the triangle is: [tex]\frac{\sqrt{255}}{4}s^2[/tex]

The given parameter can be represented as:

[tex]Base = s[/tex]

[tex]Length = 8s[/tex]

See attachment for illustration; where h represents the height of the triangle.

Next, we calculate the height of the triangle using Pythagoras theorem

[tex](8s)^2 = h^2 + (\frac 12s)^2[/tex]

[tex]64s^2 = h^2 + \frac 14s^2[/tex]

Collect like terms

[tex]h^2 = 64s^2 -\frac 14s^2[/tex]

Take LCM

[tex]h^2 = \frac{4 \times 64 -1}{4}s^2[/tex]

[tex]h^2 = \frac{255}{4}s^2[/tex]

Take square roots of both sides

[tex]h = \sqrt{\frac{255}{4}s^2[/tex]

[tex]h = \frac{\sqrt{255}}{2}s[/tex]

The area of the triangle is then calculated using:

[tex]Area = \frac 12 \times Base \times Height[/tex]

So, we have:

[tex]Area = \frac 12 \times s \times \frac{\sqrt{255}}{2}s[/tex]

[tex]Area = \frac{\sqrt{255}}{4}s^2[/tex]

Hence, the mathematical expression for the area of the triangle is: [tex]\frac{\sqrt{255}}{4}s^2[/tex]

Read more about areas of triangles at:

https://brainly.com/question/11952845

Ver imagen MrRoyal