Answer:
Float is travelling at speed of 3.86 m/s
Explanation:
As per Doppler's effect we know that when source and observer moves relative to each other then the frequency is different from actual frequency
so here when source moves closer to the observer
[tex]f_1 = f_o(\frac{v}{v - v_s})[/tex]
now we have
[tex]356 = f_o(\frac{v}{v - v_s})[/tex]
again when source moves away from the observer then we have
[tex]f_2 = f_o(\frac{v}{v + v_s})[/tex]
[tex]348 = f_o(\frac{v}{v + v_s})[/tex]
now divide above two equations
[tex]\frac{356}{348} = \frac{v + v_s}{v - v_s}[/tex]
[tex]1.023 = \frac{v + v_s}{v - v_s}[/tex]
[tex]1.023( v - v_s) = (v + v_s)[/tex]
here we know that the speed of sound in air is 340 m/s
so we have
[tex]1.023(340 - v_s) = (340 + v_s)[/tex]
[tex]7.816 = 2.023 v_s[/tex]
now we have
[tex]v_s = 3.86 m/s[/tex]