Respuesta :
Answer:
The height of the density function is [tex]\frac{1}{22}[/tex]
Step-by-step explanation:
Given : A random variable X follows the continuous uniform distribution with a lower bound of −4 and an upper bound of 18.
To find : What is the height of the density function f(x)?
Solution :
According to question,
The height of the density function is given by,
[tex]f(X)=\frac{1}{b-a}[/tex]
Where, a is the lower bound a=-4
b is the upper bound b=18
Substitute the value in the formula,
[tex]f(X)=\frac{1}{18-(-4)}[/tex]
[tex]f(X)=\frac{1}{18+4}[/tex]
[tex]f(X)=\frac{1}{22}[/tex]
Therefore, The height of the density function is [tex]\frac{1}{22}[/tex]
Answer:
Height of density function is equal to [tex]\dfrac{1}{22}[/tex].
Step-by-step explanation:
Given that
Lower bound= -4 and upper bound=18 and we need to find height of density function.
We know that height ofProbability density function given as
[tex]Height =\dfrac{1}{Upper\ bound -lower\ bound}[/tex]
Now by putting the values in the above formula we will get
[tex]Height =\dfrac{1}{18 -(-4)}[/tex]
[tex]Height =\dfrac{1}{22}[/tex]
So height of density function is equal to [tex]\dfrac{1}{22}[/tex].
