Answer:
final displacement lf = 0.39 m
Explanation:
from change in momentum equation:
[tex]\delta p = m \sqrt(2g * y/x)* [\sqrt li + \sqrt lf][/tex]
given: m = 0.4kg, y/x = 19/85, li = 1.9 m,
\delta p = 1.27 kg*m/s.
putting all value to get the final displacement value
[tex]1.27 = 0.4\sqrt(2*9.81 *(19/85))* [\sqrt 1.9 + \sqrt lf][/tex]
final displacement lf = 0.39 m
