Answer:
The new volume of the gas is 1955.65 L.
Explanation:
Initial temperature of the gas in the balloon =[tex]T_1[/tex]= 22°C = 295.15 K
Initial volume of the the gas [tex]V_1[/tex]= 1820 L
Final temperature of the gas in the balloon[tex]T_2[/tex] = 84°C = 317.15 K
Final volume of the the gas = [tex]V_2=?[/tex]
Under constant pressure and amount of gas, the gas will follow Charles' law:
[tex]\frac{V_1}{T_1}=\frac{V_2}{T_2}[/tex] (Constant pressure)
[tex]V_2=\frac{1820 L\times 317.15 K}{295.15 K}=1955.65 L[/tex]
The new volume of the gas is 1955.65 L.
