Answer:
The equations are
1) [tex]H_{2}Se+H_{2}O--> H_{3}O^{+}+HSe^{-}[/tex]
2) [tex]HSe^{-} +H_{2}O--> H_{3}O^{+}+Se^{-2}[/tex]
Explanation:
There are two ionization steps in the dissociation of hydroselenic acid.
In first dissociation the H₂Se loses one proton and forms hydrogen selenide ion as shown below:
[tex]H_{2}Se+H_{2}O--> H_{3}O^{+}+HSe^{-}[/tex]
The next step is again removal of a proton from the base formed above.
[tex]HSe^{-} +H_{2}O--> H_{3}O^{+}+Se^{-2}[/tex]
