An atomic nucleus with a rest mass energy of 7134 MeV is accelerated to 99.217% the speed of light relative to the lab frame. What is the Kinetic Energy in MeV of the atomic nucleus in the lab frame? Assume 4 significant figures.

Respuesta :

Answer:

4.999 × 10MeV

Explanation:

Kinetic energy is related to the rest energy by the Lorentz transformation equation as shown below.

Kinetic energy in the lab frame K= ( γ -1 ) Eo

The Lorentz constant γ = [tex]1/\sqrt{1-v^2/c^2}[/tex]

So γ =  [tex]1/\sqrt{1- (0.99217 c)^2/c^2}[/tex]= 8.0067

K = (8.0067-1)(7134) = 49986 MeV

                                       =49,999 MeV ( 4 significant figures)