Answer:
Part a)
[tex]Q = 6.36 \times 10^{18} J[/tex]
Part b)
[tex]t = 144.11 years[/tex]
Explanation:
Part a)
Energy required to raise the temperature of water from 17.8 degree C to 21.6 degree C is given by formula
[tex]Q = ms\Delta T[/tex]
here we know that
Here the volume of the water is given as
[tex]V = 4.00 \times 10^{11} m^3[/tex]
now the mass of water is
[tex]m = density \times volume[/tex]
[tex]m = 4.00 \times 10^{14} kg[/tex]
now the heat required is
[tex]Q = (4 \times 10^{14})(4186)(21.6 - 17.8)[/tex]
[tex]Q = 6.36 \times 10^{18} J[/tex]
Part b)
As we know that power is supplied at
[tex]P = 1400 MW[/tex]
so here we know
[tex]P = \frac{Q}{t}[/tex]
so here we have
[tex]t = \frac{Q}{P}[/tex]
[tex]t = \frac{6.36 \times 10^{18}}{1400 \times 10^6}[/tex]
[tex]t = 4.54 \times 10^9 s[/tex]
[tex]t = 144.11 years[/tex]