Respuesta :
Answer with explanation:
For a Lopsided coin ,probability of getting Head is equal to [tex]\frac{1}{3}[/tex] For a Lopsided coin ,probability of getting Tail is equal to [tex]\frac{1}{3}[/tex].
→Probability of getting Tail > Probability of getting Head
→Coin is heavier from tail side and lighter from Head side.
→→We have to Calculate number of flips of coin that is needed to have both heads and tails appear at least once.
[tex]\rightarrow P(\text{Head})=\frac{1}{3}\\\\ \frac{1}{3} \times x=1\\\\x=3\\\\\rightarrow P(\text{Tail})=\frac{2}{3}\\\\ \frac{2}{3} \times y=1\\\\y=\frac{3}{2}[/tex]
→We need to find common multiple of 3 and [tex]\frac{3}{2}[/tex].
Least common multiple of 3 and [tex]\frac{3}{2}[/tex] is 6.
→So,on Average number of flips of this coin are needed to have both heads and tails appear at least once=6 tosses
