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A meter stick whose mass is 310 grams lies on ice. You pull at one end of the meter stick, at right angles to the stick, with a force F = 9 newtons. The ensuing motion of the meter stick is quite complicated, but what are the initial magnitude and direction of the rate of change of the momentum of the stick, dPtot/dt, when you first apply the force?

Respuesta :

Answer:

[tex]\frac{dp}{dt} = 9N[/tex] and the direction of change of momentum will be in the direction of the applied force.

Explanation:

Given data in the question:

mass of the meter stick, ma = 310 grams

Applied force on the stick, F = 9 Newtons

Now, from the Newton's second law of motion we have

Net force = change in momentum per unit change in time

or

[tex]F=\frac{dp}{dt}[/tex]

or

[tex]\frac{dp}{dt} = 9N[/tex]

and the direction of change of momentum will be in the direction of the applied force.

okpalawalter8

We have that for the Question "A meter stick whose mass is 310 grams lies on ice. You pull at one end of the meter stick, at right angles to the stick, with a force F = 9 newtons. The ensuing motion of the meter stick is quite complicated, but what are the initial magnitude and direction of the rate of change of the momentum of the stick, dPtot/dt, when you first apply the force?"

it can be said that

  • The direction is to the right
  • The initial magnitude is [tex]29.03m/s^2[/tex]

From the question we are told

mass is 310 grams, with a force F = 9 newtons

Generally the equation for the magnitude of rate of change of momentum is mathematically given as

[tex]\frac{dp}{dt} = F\\\\= 9N[/tex]

The course of the rate of trade of momentum is the same as the path of the applied force that is to the right

The initial acceleration of the stick is

[tex]a = \frac{F}{m}\\\\= \frac{9}{0.31}\\\\\= 29.03 m/s^2[/tex]

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https://brainly.com/question/23379286

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