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For a tubular section with outside diameter 68 mm and inside diameter 49 mm. If the tube was subjected to a torque of 1996 Nm, what would be the maximum stress in the material, fts?

Respuesta :

Answer:

[tex]\sigma = 44.286 N/mm2[/tex]

Explanation:

given data:

outside diameter = 68 mm

inside diameter = 49 mm

torque = 1996 Nm =1996000 Nmm

we know that torque for tubular section is given as

[tex]T = \frac{\pi}{16} \sigma \frac{D_0^4- D_i^4}{D_0}[/tex]

Plugging all value to get required value of maximum stress [tex]\sigma[/tex]

[tex]1996000 = \frac{\pi}{16} \sigma \frac{68^4 - 49^4}{68}[/tex]

[tex]\sigma = 44.286 N/mm2[/tex]

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