Answer:
Speed of light in the glass [tex]v=2.26\times 10^8 ms^{-1}[/tex]
Explanation:
In this question we have given
angle of polaization,p=[tex]53^o[/tex]
we have to find the speed of light in the glass,v=?
We know that, refractive index of glass can be determined by following formula
[tex]n=\frac{c}{v}[/tex]................(1)
here,
c- speed of light in air
v-speed of light in glass
we also know according to brewester's law refrective index of glass is given as
n=tanp......................(2)
here p-angle of polarization
From equation (1) and equation (2)
we got
[tex]\frac{c}{v}=tanp[/tex]
put value of c=[tex]3\times 10^8 ms^{-1}[/tex] and p=[tex]53^o[/tex] in equation 3
we got
[tex]\frac{3\times 10^8 ms^{-1}}{v}=tan53[/tex]
[tex]v=\frac{3\times 10^8 ms^{-1}}{tan53}\\v=\frac{3\times 10^8 ms^{-1}}{1.32}\\v=2.26\times 10^8 ms^{-1}[/tex]