Answer:
It is a homogeneus function of degree 1.
Step-by-step explanation:
Let us take [tex]F(x_1,x_2)=b_0x_2+b_1x_1+b_2x_2[/tex] and a constant [tex]\lambda \in \mathbb{R}[/tex]. It holds that
[tex]F(\lambda x_1, \lambda x_2)=b_0\lambda x_2+b_1\lambda x_1+b_2\lambda x_1=\lambda(b_0x_2+b_1x_1+b_2x_2)=\lambda F(x_1,x_2)[/tex]
which shows that [tex]F(x_1,x_2)[/tex] is homogeneus of degree 1.
