Answer: The uncertainty in proton's momentum is [tex]1.3\times 10^{-20}kg.m/s[/tex]
Explanation:
The equation representing Heisenberg's uncertainty principle follows:
[tex]\Delta x.\Delta p\geq \frac{h}{2\pi}[/tex]
where,
[tex]\Delta x[/tex] = uncertainty in position = d = [tex]7.8\times 10^{-15}m[/tex]
[tex]\Delta p[/tex] = uncertainty in momentum = ?
h = Planck's constant = [tex]6.627\times 10^{-34}kgm^2/s^2[/tex]
Putting values in above equation, we get:
[tex]\Delta p=\frac{6.627\times 10^{-34}kgm^2/s^2}{2\times 3.14\times 7.8\times 10^{-15}m}\\\\\Delta p=1.3\times 10^{-20}kg.m/s[/tex]
Hence, the uncertainty in proton's momentum is [tex]1.3\times 10^{-20}kg.m/s[/tex]
