Answer:
Equivalent resistance of the combination is 24 ohms.
Explanation:
Resistance 1, [tex]R_1=7\ \Omega[/tex]
Resistance 2, [tex]R_2=6\ \Omega[/tex]
Resistance 3, [tex]R_3=11\ \Omega[/tex]
Voltage of battery, V = 12 volt
These three resistors are connected in series whose equivalent is given by :
[tex]R_{eq}=R_1+R_2+R_3[/tex]
[tex]R_{eq}=7+6+11[/tex]
[tex]R_{eq}=24\ \Omega[/tex]
So, the equivalent resistance of the combination is 24 ohms. Hence, this is the required solution.
