Answer:
9.44 eV
Explanation:
q = Amount of charge = 86.3 μC = 86.3 x 10⁻⁶ C (Since 1 μC = 10⁻⁶ C)
V = Electric potential of the charge = 17.5 Volts
U = Amount of electric potential energy carried by charge
Amount of electric potential energy carried by charge is given as
U = q V
Inserting the values
U = (86.3 x 10⁻⁶) (17.5)
U = 0.00151 J
U = [tex]\frac{0.00151}{1.6\times 10^{-19}}[/tex]
U = 9.44 eV
KE = Kinetic energy the charge could have
Using conservation of energy
KE = U
KE = 9.44 eV
