Answer:
Step-by-step explanation:
Given that
mu = 1502.5 pages
Sample mean x bar = 1511.4 pages
Std deviation =s= 35.7 pages
Sample size n = 40
By assuming random samples since only sample std dev is know we can say that sample mean x bar follows a t distribution with
mean =1511.4 and std error =[tex]\frac{35.7}{\sqrt{40} } \\=5.64[/tex]
Test statistic t = Mean diff/STd error = 1.613
df = 39