The University of Metropolis requires its students to pass an examination in college-level mathematics before they can graduate. The students are given three chances to pass the exam; 61% pass it on their first attempt, 63% of those that take it a second time pass it then, and 48% of those that take it a third time pass it then. (Assume that all students who do not pass the first or second time elect to take the test again.) What percent of the students take the test three times? (Round your answer to one decimal place.)

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sqdancefan sqdancefan · Answer 1 · 2019-08-21T22:54:19+02:00

Answer:

14.4%

Step-by-step explanation:

Of the 39% who fail the first exam, 37% fail a second time. Those are the ones who take it 3 times:

0.39 × 0.37 = 0.1443 ≈ 14.4%

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andromache andromache · Answer 2 · 2022-02-17T13:47:36+01:00

The percent of the students take the test three times is 6.9%.

The probability of fail in first attempt should be

= 1 - 0.61

= 0.39

And, The probability of fail in second attempt should be

= 1 - 0.63

= 0.37

And, the third attempt should be 0.48

So, the percentage should be

[tex]= 0.39 \times 0.37 \times 0.48[/tex]

= 6.9%

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