Answer:
511797.76 eV
Explanation:
Mass of electron = Mass of positron = 9.11×10⁻³¹ kg
Mass of annihilation
Δm = Mass of electron + Mass of positron
⇒Δm = 9.11×10⁻³¹+9.11×10⁻³¹
From Einstein's Equation
[tex]E=\Delta c^2\\\Rightarrow E=18.22\times 10^{-31}\times (3\times 10^8)^2\ J[/tex]
1 eV = 1.602 × 10⁻¹⁹ J
[tex]\frac{18.22\times 10^{-31}\times (3\times 10^8)^2}{1.602\times 10^{-19}}=1023595.51\ eV[/tex]
Energy of each photon is
[tex]\frac{1023595.51}{2}=511797.76\ eV[/tex]
∴ Energy of each of the two photons produced in an electron-positron annihilation is 511797.76 eV
