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21-08-2019
Physics

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A spring stretches by 21.0 cm when a 135 N object is attached. What is the weight of a fish that would stretch the spring by 31.0 cm? A) 279 N B) 199 N C) 91 N D) 145 N

Respuesta :

23-08-2019

Answer:

B) 199N

Explanation:

Spring constant k = force/ extension = 135 /21 =6.42857 N/cm

Now force = k x extension = 6.42857 x 31 = 199 N.

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