1. randomly choosing a white counter from a bag of 12 red.
counters, 12 white counters, 12 green counters, and 12 blue
counters

Respuesta :

What is the question ?

The white counter value "[tex]\bold{\frac{1}{4}}[/tex]".

permutation:

Red counters= 12

white counters= 12

green counters = 12

blue counters=12

P(white counters) = ?

Calculating the total outcomes:

[tex]\to 12+12+12+12=48[/tex]

Using the formula for calculating the value of the white counter: [tex]\to \text{P (white counters)} =\frac{\text{Number of favorable outcome}}{\text{Total number of outcoms}}[/tex]

                                  [tex]= \frac{N(E)}{N(S)}\\\\= \frac{12}{48}\\\\= \frac{1}{4}\\[/tex]

Therefore, the white counter value "[tex]\bold{\frac{1}{4}}[/tex]".

Find out more information about the white counter here:

brainly.com/question/26033414