Answer:
The magnetic field of the particle is 1.5 T.
(C) is correct option.
Explanation:
Given that,
Momentum of particle [tex]p=4.8\times10^{-16}\ kg m/s[/tex]
Radius = 1.0 km
Charge of the particle [tex]q=2\times1.6\times10^{-19}\ C[/tex]
We need to calculate the magnetic field
Using relation of radius of path in magnetic field
[tex]r=\dfrac{mv}{qB}[/tex]
Here mv = p
[tex]B=\dfrac{p}{qr}[/tex]
Put the value into the formula
[tex]B=\dfrac{4.8\times10^{-16}}{1000\times2\times1.6\times10^{-19}}[/tex]
[tex]B=1.5\ T[/tex]
Hence, The magnetic field of the particle is 1.5 T.
