An ideal frictionless DC permanent magnet motor operating from a 24 V source has a no load speed of 240 radians/sec and an armature resistance of 0.2 Ohms. Compute the stall torque of the motor in Newton-meters.

Respuesta :

Answer:

12 N-m

Explanation:

The dc motor is operating at 24 V that is its terminal voltage V =24 V

Armature resistance [tex]R_a[/tex] = 0.2 ohm

No load speed = 240 radian /sec

For motor we know that [tex]V=E_b+iR_a[/tex] as the motor is on no load so [tex]E_b=0[/tex] so [tex]i=\frac{V}{R_a}=\frac{24}{0.2}=120A[/tex]

Power developed in the motor [tex]P=Vi=120\times 24=2880W[/tex]

Now we know that power = torque× angular speed

So [tex]2880=\tau \times 240[/tex]

[tex]\tau =\frac{2880}{240}=12N-m[/tex]