Answer:
3.13 s difference
Explanation:
Velocity of sound in air at 20°C = 331 + .6 X 20 = 343 m s⁻¹
Velocity of sound in water at 20°C = 3 X 343 = 1029 m s⁻¹
Time taken by sound in air to cover 1 mile or 1609 m distance
=[tex]\frac{1609}{343}[/tex]
= 4.69 s
Time taken by sound in water to cover 1 mile or 1609 m distance
= [tex]\frac{1609}{1029}[/tex]
1.56 s
difference = 3.13 s .