Answer:
10.575 m/s
Explanation:
According to the conservation of energy, the potential energy is equal to the kinetic energy.
m = Mass of water
g = Acceleration due to gravity = 9.81 m/s²
h = Height of water = 5.7 m
v = Velocity of water
PE = KE
[tex]mgh=\frac{1}{2}mv^2\\\Rightarrow \not{m}gh=\frac{1}{2}\not{m}v^2\\\Rightarrow v^2=2gh\\\Rightarrow v=\sqrt{2gh}\\\Rightarrow v=\sqrt{2\times 9.81\times 5.7}=10.575\ m/s[/tex]
∴ Speed of water out of pipe is 10.575 m/s
The speed of water coming out of pipe will be [tex]V=10.575\frac{m}{s}[/tex]
It is given that the height from which water comes out will be h=5.70 m
From Bernoullis principle total energy will remains constant
since the pressure is atmospheric so change of pressure will be zero
Here we have ,
m = Mass of water
g = Acceleration due to gravity = 9.81 m/s²
h = Height of water = 5.7 m
v = Velocity of water
So the from conservation of energy potential energy of water will be equal to the kinetic energy of water.
PE=KE
[tex]mgh=\dfrac{1}{2} mv^{2}[/tex]
[tex]v=\sqrt{2gh}[/tex]
putting the values in the equation
[tex]v=\sqrt{2\times9.81\times 5.7}[/tex]
[tex]v=10.575 \dfrac{m}{s}[/tex]
Thus the speed of water coming out of pipe will be [tex]V=10.575\frac{m}{s}[/tex]
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