Answer:
1.98 x 10⁻⁷ F
Explanation:
w = width of the sheet = 5.9 cm = 0.059 m
L = length of the sheet = 5.6 m
Area of the sheet is given as
A = L w = (5.6) (0.059) = 0.3304 m²
d = distance between the sheets = 3.1 x 10⁻⁵ m
k = dielectric constant of teflon = 2.1
Capacitance is given as
[tex]C = \frac{k\epsilon _{o}A}{d}[/tex]
[tex]C = \frac{(2.1)(8.85\times 10^{-12})(0.3304)}{3.1\times 10^{-5}}[/tex]
C = 1.98 x 10⁻⁷ F
