What is Question I (if m<EBF = 117°, fine m<ABE)

Answer:
m∠ABE = 27°
Step-by-step explanation:
* Lets look to the figure to solve the problem
- AC is a line
- Ray BF intersects the line AC at B
- Ray BF ⊥ line AC
∴ ∠ABF and ∠CBF are right angles
∴ m∠ABF = m∠CBF = 90°
- Rays BE and BD intersect the line AC at B
∵ m∠ABE = m∠DBE ⇒ have same symbol on the figure
∴ BE is the bisector of angle ABD
∵ m∠EBF = 117°
∵ m∠EBF = m∠ABE + m∠ABF
∵ m∠ABF = 90°
∴ 117° = m∠ABE + 90°
- Subtract 90 from both sides
∴ m∠ABE = 27°
Answer:
m∠ABE = 27°
Step-by-step explanation:
In the figure attached, It is given that m∠EBF = 117°
and BF ⊥ AC (BF is perpendicular to segment AC)
Therefore, m∠ABF = m∠CBF = 90°
Now we know m∠EBF = m∠ABE + m∠ABF
117° = m∠ABE + 90°
m∠ABE = 117° - 90°
= 27°
Therefore, measure of angle ABE is 27°.