Answer:
[tex]\large\boxed{y=\dfrac{9}{8}x-\dfrac{5}{16}}[/tex]
Step-by-step explanation:
The slope-intercept form of an equation of a line:
[tex]y=mx+b[/tex]
m - slope
b - y-intercept
We have the equation of a line in the standard form (Ax + By = C).
Convert it to the slope-intercept form:
[tex]18x-16y=5[/tex] subtract 18x from both sides
[tex[18x-18x-16y=-18x+5[/tex]
[tex]-16y=-18x+5[/tex] divide both sides by (-16)
[tex]\dfrac{-16y}{-16}=\dfrac{-18x}{-16}+\dfrac{5}{-16}\\\\y=\dfrac{18:2}{16:2}x-\dfrac{5}{16}\\\\y=\dfrac{9}{8}x-\dfrac{5}{16}[/tex]
