Answer:
The sound energy impinges on the microphone each second is [tex]3.285\times10^{-8}\ J/s[/tex].
Explanation:
Given that,
Sound power = 25.0 W
Area = 0.500 cm²
Radius r = 55.0
(a). We need to calculate the sound intensity
Using formula of sound intensity
[tex]I=\dfrac{P}{A}[/tex]
[tex]I=\dfrac{25.0}{4\pi\times(55)^2}[/tex]
[tex]I=0.000657=0.657\times10^{-3}\ W/m^2[/tex]
(b). We need to calculate the sound energy impinges on the microphone each second
Using formula of intensity
[tex]P=IA[/tex]
Put the value into the formula
[tex]P=0.657\times10^{-3}\times0.500\times10^{-4}[/tex]
[tex]P=3.285\times10^{-8}\ J/s[/tex]
Hence, The sound energy impinges on the microphone each second is [tex]3.285\times10^{-8}\ J/s[/tex].
