Answer:
40 mm
Explanation:
[tex]L_o[/tex]=Proper Length of rod = 2.05 m
Speed of rod = 6.01×10⁷ m/s
Length contraction
[tex]L=\sqrt{1-\frac{v^2}{c^2}}L_o\\\Rightarrow L=\sqrt{1-\frac{(6.01\times 10^7)^2}{(3\times 10^8)^2}}\times 2.05=2.00844[/tex]
Final Length will be 2.01 m
So length that is contracted is 2.05-2.01 = 0.04 m
The length is contracted by 40 mm.