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Review Interactive Solution 4.47 in preparation for this problem. A 88.8-kg baseball player slides into second base. The coefficient of kinetic friction between the player and the ground is μk = 0.531. (a) What is the magnitude of the frictional force? (b) If the player comes to rest after 1.38 s, what is his initial speed?

Respuesta :

Answer:

frictional force = 462.56 N

initial velocity is 7.176 m/s

Explanation:

given data

mass = 88.8 kg

μk = 0.531

to find out

magnitude and  initial speed

solution

we know that frictional force equation that is

frictional force =  μk Fn

put these value we get

frictional force = 0.531 (88.8) × (9.81)

frictional force = 462.56 N

and

initial speed calculate by force equation that is

force = mass × a

a = force  / mass

a = 462.56 / 88.8

a = 5.20 m/s²

so we know

V = [tex]V_{0}[/tex] + at

[tex]V_{0}[/tex]  =  5.20 × 1.38

[tex]V_{0}[/tex]  = 7.176 m/s

so initial velocity is 7.176 m/s

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