Answer:
[tex]1.6\times 10^{-7}[/tex] N
[tex]2.4\times 10^{-7}[/tex] N
Explanation:
[tex]i_{1}[/tex] = 1 A
[tex]i_{2}[/tex] = 4 A
[tex]r[/tex] = distance between the two wire = 5 m
[tex]F[/tex] = Force per unit length acting between the two wires
Force per unit length acting between the two wires is given as
[tex]F = \frac{\mu _{o}}{4\pi }\frac{2i_{1}i_{2}}{r}[/tex]
[tex]F = (10^{-7})\frac{2(1)(4)}{5}[/tex]
[tex]F = 1.6\times 10^{-7}[/tex] N
[tex]r'}[/tex] = distance of each wire from the midpoint = 2.5 m
Magnetic field midway between the two wires is given as
[tex]B = \frac{\mu _{o}}{4\pi } \left \left ( \frac{2i_{2}}{r'} \right - \frac{2i_{1}}{r'} \right \right ))[/tex]
[tex]B = (10^{-7}) \left \left ( \frac{2(4)}{2.5} \right - \frac{2(1)}{2.5} \right \right ))[/tex]
[tex]B = 2.4\times 10^{-7}[/tex]
